Write the value if k for which the system of equations x+y -4 =0 and 2x + ky -3=0 has no solution 1*2=2 Question Write the value if k for which the system of equations x+y -4 =0 and 2x + ky -3=0 has no solution 1*2=2 in progress 0 Math Jasmine 1 month 2021-08-17T05:53:12+00:00 2021-08-17T05:53:12+00:00 1 Answer 0 views 0

## Answers ( )

Answer:Given,

The system of equation are

x – ky = 2

3x + 2y = – 5

To find, the value of k = ?

Here, a_{1} =1,b_{1} =-k,c_{1} =2 and

a_{2} =3,b_{2} =2,c_{2} =-5

The condition of the the system of equation has a unique solution

\dfrac{a_{1}}{a_{2}} \neq \dfrac{b_{1}}{b_{2}}

∴ \dfrac{1}{3} \neq \dfrac{-k}{2}

⇒ k\neq \dfrac{-2}{3}

Hence, k\neq \dfrac{-2}{3}