Write the value if k for which the system of equations x+y -4 =0 and 2x + ky -3=0 has no solution 1*2=2

Question

Write the value if k for which the system of equations x+y -4 =0 and 2x + ky -3=0 has no solution 1*2=2

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Jasmine 1 month 2021-08-17T05:53:12+00:00 1 Answer 0 views 0

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    2021-08-17T05:54:37+00:00

    Answer:

    Given,

    The system of equation are

    x – ky = 2

    3x + 2y = – 5

    To find, the value of k = ?

    Here, a_{1} =1,b_{1} =-k,c_{1} =2 and

    a_{2} =3,b_{2} =2,c_{2} =-5

    The condition of the the system of equation has a unique solution

    \dfrac{a_{1}}{a_{2}} \neq \dfrac{b_{1}}{b_{2}}

    ∴ \dfrac{1}{3} \neq \dfrac{-k}{2}

    ⇒ k\neq \dfrac{-2}{3}

    Hence, k\neq \dfrac{-2}{3}

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