Write the value of x for which x, x+2 , 2x +3 are three consecutive terms of an A.P ​

Question

Write the value of x for which x, x+2 , 2x +3 are three consecutive terms of an A.P ​

in progress 0
Alice 3 weeks 2021-08-20T11:05:29+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-20T11:06:38+00:00

    Answer:

    Given,

    x+2,2x,2x+3 are in A.P.

    ⇒(2x)−(x+2)=(2x+3)−(2x)

    2x−x−2=2x+3−2x

    x−2=3

    ∴x=5

    The consecutive numbers are : 5+2,2(5),2(5)+3

    ⇒7,10,13

    Please select me as braiinalist

    0
    2021-08-20T11:07:24+00:00

    Answer:

    x=5

     

    since the above three are the consecutive terms of an ap .

    therefore ,

    a2-a1=a3-a2 i;e

    2x-(x-2) = 2x +3 (-2x)

    x-2=3

    x=5 .

Leave an answer

Browse
Browse

18:9+8+9*3-7:3-1*13 = ? ( )